LIS Links

First and Largest Academic Social Network of LIS Professionals in India

LIS Links Becoming More Social

LIS Links Mailing List (Broadcast Message)

Birthdays

Birthdays Today

Latest Activity

Narendra Pal shared a profile on Facebook
Thumbnail

Amita mishra

yesterday
Profile IconLIS Links now has birthdays
yesterday
Dr. U. Pramanathan posted blog posts
2 more…
yesterday
Dr. U. Pramanathan posted events
yesterday
Dr. U. Pramanathan updated their profile
Wednesday
Urvashi kaushik replied to Sunil K Upneja's discussion Clarification regarding CAS promotion of College Librarian
Wednesday
S. Jaffer Basha left a comment for Dr Jolly Varghese U
Tuesday
Dr. U. Pramanathan posted blog posts
1 more…
Tuesday
Dr. U. Pramanathan posted events
Tuesday
ASHOKKUMAR SINGH commented on Dr. U. Pramanathan's blog post Recruitment of Librarian Gr.II/Librarian Senior, Assistant Librarian, Library Restorer & Documentist @ Baba Farid University of Health Sciences (BFUHS), Faridkot, Punjab.
Tuesday
ASHOKKUMAR SINGH commented on Dr. U. Pramanathan's blog post Recruitment of Librarian Gr.II/Librarian Senior, Assistant Librarian, Library Restorer & Documentist @ Baba Farid University of Health Sciences (BFUHS), Faridkot, Punjab.
Tuesday
Sanraj Roy posted an event
Thumbnail

Advanced Training programme on Bibliometrics and Research Output Analysis at Library Network Centre, Infocity, Gandhinagar382007, Gujarat, India.

December 2, 2024 to December 6, 2024
Monday
0 Comments
SHWETHA KV posted a discussion

CBSE Inspection of School Libraries

Monday
0 Comments
Sunil K Upneja posted a discussion

Clarification regarding CAS promotion of College Librarian

Monday
1 Comment
Dr. Mahabaleshwara Rao Baikady posted an event

6th NACML (National Conference on Management of Modern Libraries) - 2025 at Dr. TMA Pai Hall

February 21, 2025 at 8am to February 22, 2025 at 5pm
Monday
0 Comments
Saanvi Singh posted a status
"School Librarian Vacancy for 125 Post in Tripura: https://shorturl.at/GEgWl"
Saturday
0 Comments
Urvashi kaushik and Vikram Jain are now friends
Nov 15
Urvashi kaushik replied to Mrs. Vishakha R. Rajguru's discussion Evidence for CBSE Librarians Status in Maharashtra or Maharashtra govt.
Nov 15
Urvashi kaushik replied to Mrs. Vishakha R. Rajguru's discussion Evidence for CBSE Librarians Status in Maharashtra or Maharashtra govt.
Nov 15
Profile IconRenuka M Yalamali, SAMEER SAI PAINKRA, Annanya and 6 more joined LIS Links
Nov 15

UGC NET 1996

Q.1 :- There are a total of 50 relevant document in a collection. In response to a query,only 30 document are retrieved, of these ,only 10 were relevant.What is the recall percentage.
Ans:-
A} 20%
B} 33%
C} 40%
D} 60%

Ans :- B} 33%

Dear lis professionals,
Can anyone tell me how to get this answer?
Is their any method?

Views: 646

▶ Reply to This

Replies to This Forum

Permalink Reply by Langmuanjohn Tonsing on February 12, 2012 at 23:18

hello Sangeeta,

Let me give a try

Formula is Recall = Number of relevant result retrieve / Number of non-retrieve document + Number of relevant result retrieve

so, Number of relevant result retrieve=10,

     Number of non-retrieve documents=20 (50-30=20)

Recall=10/20+10

         =10/30

         = 0.33

         =0.33*100=33% (i.e. 33/100=0.33)

This is wat i think according to the formula, if it is wrong let me know.

Permalink Reply by Langmuanjohn Tonsing on February 12, 2012 at 23:26

Sori, the last line " =0.33*100=33% (i.e. 33/100=0.33)" should be =0.33 =33% (i.e. 33/100=0.33).

Permalink Reply by Vishal Sharma on February 12, 2012 at 23:47
10*100/30=33.33%
Permalink Reply by Langmuanjohn Tonsing on February 13, 2012 at 0:28

Dear Vishal Sharma 

Can you please explain in details?

Permalink Reply by Dr.Harmanpreet Singh Sandhu on February 13, 2012 at 1:50

Very Good Question asked, with regards to upcoming pattern of the UGC NET June 2012.   Recall percentage is the percentage of documents retrieved which were of actually requested or relevant documents with reference to the query.

To find out the Recall % = Total no. of relevant documents delivered / Total no. of documents deliverd * 100

  i:e   10/30*100 = 33.33 %

When searching in google we don't know the total relevant documents uploaded on the net ..... so the recall % is found out by this formula only.

Permalink Reply by Langmuanjohn Tonsing on February 13, 2012 at 1:58

Dear Harmanpreet,

Can you also please give the formula for precision?

Permalink Reply by Sangeeta Dubey on February 13, 2012 at 18:41

Lot of thanks for your opinion.

Permalink Reply by Vishal Sharma on February 13, 2012 at 18:53
welcome ma'am
Permalink Reply by K. Nagaraja Rao on February 14, 2012 at 2:43

According to me: Recall is intersection of relevant documents and retrieved documents divided by relevant documents in the system:

thus the intersection gives only 10 out of 50 relevant documents. 1/5*100

Which is 20%. To get 33%, the question should say 30 relevant documents from a total collection.

\mbox{recall}=\frac{|\{\mbox{relevant documents}\}\cap\{\mbox{retrieved documents}\}|}{|\{\mbox{relevant documents}\}|}
formula taken from wikipedia.
Permalink Reply by Sangeeta Dubey on February 14, 2012 at 2:52

Thank you for your efforts sir.

I ll check it. n inform you.

rawishPermalink Reply by rawish on March 4, 2012 at 21:28

mam if u got the recall value for your questions plz tell me the correct answer and also the method.thanks

RSS

© 2024   Created by Dr. Badan Barman.   Powered by

Badges  |  Report an Issue  |  Terms of Service

Koha Workshop