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Applications are invited from eligible candidates for recruitment to the post of "Librarian and Library Apprentice Trainees" on a temporary contract basis
The Amrita Vishwa Vidyapeetham, Amaravati Campus, Andhra Pradesh is inviting applications from qualified candidates for the post of a Assistant Librarian.
IISER Thiruvananthapuram invites online application from eligible candidates for the Library Superintendent (UR-1) Group: B non-teaching position on regular basis.
KLA-CPD is organizing a One-Day National Workshop on ‘AI Tools for Teaching, Learning, and Research’,
February 21, 2026 from 9:30am to 3:30pmOne-Day Seminar on Research Journal Article Writing and Publishing
February 16, 2026 from 10am to 4pm
User Awareness Programme on ORCID, IRINS and INFLIBNET Services for Scholarly Communities at Avantika University, Ujjain, Madhya Pradesh on March 20, 2026.
March 20, 2026 from 9am to 5pmOnline Webinar on One Nation and One Subscription (ONOS)
February 21, 2026 from 6pm to 8pmResponsible Research in the AI Era: Ethics, Authorship and Scholarly Practices
February 7, 2026 from 8:30am to 5:30pm
Online applications are invited from eligible candidates for appointment to the Semi-Professional Assistant, Library Attendant Group B & C posts in the Manipur University, Canchipur, Manipur.
NIMHANS, Bengaluru, invites applications for the Library Assistant vacant posts through online mode from Indian nationals residing in India and abroad.
UGC NET 29 June 2014 Paper I Answer Key
Replies to This Forum
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Permalink Reply by Aijaz Ahmad Bhat on
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Q. No. 13. The first web browser is worldwideweb (without spaces) not World Wide Web. Hence in this question the answer is Netscape.
For more details visit http://www.w3.org/People/Berners-Lee/WorldWideWeb.html
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Permalink Reply by Dhanya Sukumaran on
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Sir,
The first web browser was invented in 1990 by Sir Tim Berners-Lee. It was calledWorldWideWeb and was later renamed Nexus.The answer of Qu.no 13 is C.World Wide Web.
By Dhanya
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Permalink Reply by ARVIND ABHIMANYU SHINDE on
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The answer of Qu.no 13 is B
NETSCAPE
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Permalink Reply by Rama Bohra on
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QUESTION NO 4 .HOW THE ANS....IS 32 PLZ EXPLAIN IT....
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Permalink Reply by Manjunath K S on
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50-51-52-53-54-55-56-57-58-59-60-61-62-63-64-65-66-67-68-69-70-71-72-73-74-75-76-77-78-79-80-81-82-83-84-85-86-87-88-89-90-91-92-93-94-95-96-97-98-99
in this you have to leave bold numbers.
Total there are 50 Numbers in that there are 18 numbers are included with 2 and 7.
those you can minus 50-18=32
So Ans is 32
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from 50 to 99 without the digits 2 and 7 = 32
50
51 53 54 55 56 58 59 60 61 63 64 65 66 68 69 80 81 83 84 85 86 88 89 90 91 93 94 95 96 98 99 50 51 53 54 55 56 58 59 60 61 63 64 65 66 68 69 80 81 83 84 85 86 88 89 90 91 93 94 95 96 98 99
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Permalink Reply by shradhashesh on
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Dear Sir,
Your q no. 32 is wrong the right answer is D
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Dear Shradhashesh,
Qu.no 4's answer is 32...... not .....D.38. you avoid digits 2 and 7 (52 57 62 67 70 71 72 73 74 75 76 77 78 79 82 87 92 & 97).
By Dhanya
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32 IS right answer
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Permalink Reply by DR. AMRITPAL KAUR on
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Thanku Sir , Kindly upload ans. keys for II & III paper also
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Permalink Reply by Sandip Das on
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1st web browser Netscape
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